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by Dinesh Thakur Category: Control Structures

Algorithm for Armstrong Number with in Range:

step 1:Read range

step 2: Set count=0, b= 1

step 3: Repeat through step-11 while b less than or equals to range

step 4: Set sum=0

step 5: Set c=b

step 6: Repeat through step-9 while c greater than 0

step 7: a=c%10

step 8: sum=sum+(a*a*a)

step 9: c=c/10

step 10: if sum equals to b then

print b count=count+1

step 11: b=b+1

step 12: Exit

Here is the Java Example for Armstrong Number with in Range:

import java.util.Scanner;

public class ArmstrongNumberWithinRange
               public static void main(String args[])
               Scanner s=new Scanner(;
               System.out.print("Enter the Range :");
               int range=s.nextInt();
               int a,b,c,sum,count=0;
                         System.out.println(b+" is a Armstrong Number");
System.out.println("Total Armstrong Number Present With in that Range is "+count);

Armstrong Number With in Range Java

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About Dinesh Thakur

Dinesh ThakurDinesh Thakur holds an B.SC (Computer Science), MCSE, MCDBA, CCNA, CCNP, A+, SCJP certifications. Dinesh authors the hugely popular Computer Notes blog. Where he writes how-to guides around Computer fundamental , computer software, Computer programming, and web apps. For any type of query or something that you think is missing, please feel free to contact us.

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