Largest Number in an Array Java Example

Algorithm for Largest Number in an Array:

step 1: set big=0,small=0

step 2: read arr_size

step 3: create an integer array a[] of size arr_size

step 4: initialize x=0

step 5: repeat through step-7 while x less than a.length

step 6: read a[x]

step 7: x= x+ 1

step 8: Initialize x=0

step 9: repeat through step-12 while x less than a.length

step 10: print a[x]

step 11: print one space

step 12: x=x+1

step 13: initialize x=0

step 14: repeat through step-16 while x less than a.length

step 15: if a[x] greater than big then big=a[x]

step 16: x=x+1

step 17: print big

step 18: Exit

Here is the Java Example for Largest Number in an Array:

import java.util.Scanner; 
 public class LargestNumberinArray 
 { 
               public static void main(String args[]) 
       { 
               int x,y,big=0,small=0; 
               Scanner sl=new Scanner(System.in); 
               System.out.print("Enter The Size of Array : "); 
               y=sl.nextInt(); 
               int a[]=new int[y]; 
               System.out.println("Enter The Elements"); 
               for(x=0;x<a.length;x++) 
               a[x]=sl.nextInt(); 
               System.out.println("\n Print The Elements of Array \n" ); 
               for(x=0;x<a.length;x++) 
               System.out.print(a[x]+" "); 
               for(x=0;x<a.length;x++) 
                  { 
                    if(a[x]>big) 
                     { 
                       big=a[x]; 
                     } 
                  } 
 System.out.println("Largest Number in an Array is : "+big); 
       } 
 }