Write a Program for Number is Armstrong Number

In This program user ask to find out the number is Armstrong or not. “A number is Armstrong if the sum of cubes of individual digits of a number is equal to the number itself”. User declares required variables for this operation. User uses a temp variable that will use to store the value for temporary time period. Declaring while condition while (num>0) user ask to cub=num%10, num=num/10, sum=sum+ (cub*cub*cub).

Then a if-else condition if(temp==sum) then the number is Armstrong else it will not. And after creating all instance in the end display result on the screen as output.

Problem statement:

This is C program to Check out the Number is Armstrong or not.

1. Declaring the variables.
2. Using while condition along with control statements.
3. Display result on the Screen.

Here is C source code for checking out the number is Armstrong or not. The output of this program shown below. 

#include<stdio.h> 
 void main() 
 { 
    int num,temp,cub,sum=0; 
    clrscr(); 
    printf("Enter a Number : "); 
    scanf("%d",&num); 
    temp=num; 
    while(num>0) 
      { 
         cub=num%10; 
         num=num/10; 
         sum=sum+(cub*cub*cub); 
      } 
         if(temp==sum) 
               printf("Number is Armstrong"); 
             else 
               printf("Number is not Armstrong"); 
               getch(); 
 } 
 Output :