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Home » Java » Inheritance » varargs – Variable-Length Arguments Method in Java Example
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varargs – Variable-Length Arguments Method in Java Example

By Dinesh Thakur

Variable-Length Arguments Method in short varargs methods, Such methods usefulness comes into picture when you have a method that can accept a variety of arbitrary data types.

The syntax of a method that accepts a variable number of arguments is as follows:

returnType methodName ( typeName … paraName)

{

………………..

}

Here, paraName is the name of the parameter representing an array of typeName and the ellipsis (m) between typeName and paraName specifies that paraName is actually to be treated as array of zero or more elements of type typeName. Keep in mind that only one variable length parameter may be specified in a method, and may only appear on the last parameter in the list. Regular parameters may precede it.

Now let us consider a program to understand the concept of variable-length arguments. For this, we make a program to calculate average of integer numbers.

public class VarargsMethods 
{
     public static void main(String[] args)
     {
       average(15,100);
       average(15,100,150);
       average(15,100,105,210);
     }
     static void average(int...num)
     {
        double sum=0, avg;
        int i;
        for( i=0; i<num.length; i++)
            {
                 sum += num[i];
            }
        avg = sum/num.length;
        System.out.println("Average = " +avg);
     }
}

varargs - Variable-Length Arguments Method in Java Example

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About Dinesh Thakur
Dinesh ThakurDinesh Thakur holds an B.C.A, MCDBA, MCSD certifications. Dinesh authors the hugely popular Computer Notes blog. Where he writes how-to guides around Computer fundamental , computer software, Computer programming, and web apps.

Dinesh Thakur is a Freelance Writer who helps different clients from all over the globe. Dinesh has written over 500+ blogs, 30+ eBooks, and 10000+ Posts for all types of clients.


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