C Program for print a given digit as a word

The program segment given below accepts an integer number in variable digit of type int from the keyboard and if it is a single digit number (0-9), it displays the word corresponding to it;

otherwise, it displays the message Not a digit. The switch statement has a case block for each digit (0-9) and a default block to handle all other numbers. Note that the code for each case has been written on a single line to save space.

#include <stdio.h>

void main()

{

     int digit;

     clrscr();

     printf(“Enter a digit (0-9): “);

     scanf (“%d”, &digit);

     switch (digit)

    {

          case 0: printf(“Zero”); break;

          case 1: printf(“One”); break;

          case 2: printf(“Two”); break;

          case 3: printf(“Three”); break;

          case 4: printf(“Four”); break;

          case 5: printf(“Five”); break;

          case 6: printf(“Six”); break;

          case 7: printf(“Seven”); break;

          case 8: printf(“Eight”); break;

          case 9: printf(“Nine”); break;

          default:printf(“Not a digit”); break;

     }

          printf(“\n”);

          getch();

}