Armstrong Number in Java Example

Algorithm for Armstrong Number:

step 1:Set s=0

step 2: Read num

step 3: Set b=num

step 4: Repeat through step-7 while num greater than 0

step 5: r=num%10

step 6: s=s+(r*r*r)

step 7: num=num/10

step 8: If b equals to s then print “it is an Armstrong number”

Else print “it is not an Armstrong number”

step 9: Exit

Here is the Java Example for Armstrong Number:

import java.util.Scanner; 
 public class ArmstrongNumber 
 { 
                  public static void main(String args[]) 
                { 
                     Scanner s1=new Scanner(System.in); 
                     int num,b,s=0,r; 
                     System.out.println("Enter A Number"); 
                     num =s1.nextInt(); 
                     b= num; 
                     while(num>0) 
                          { 
                             r= num%10; 
                             s=s+(r*r*r); 
                             num = num/10; 
                          } 
                             if (b==s) 
               System.out.println(b+" is an Armstrong Number"); 
                             else 
               System.out.println(b+" not an Armstrong Number"); 
                  } 
 }